Optimal. Leaf size=211 \[ \frac {(e x)^{m+1} \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {d x^n}{c}\right ) (a d (B c (m+1)-A d (m-n+1))+b c (A d (m-2 n+1)-B c (m-n+1)))}{c^2 e (m+1) n (b c-a d)^2}+\frac {b (e x)^{m+1} (A b-a B) \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {b x^n}{a}\right )}{a e (m+1) (b c-a d)^2}+\frac {(e x)^{m+1} (B c-A d)}{c e n (b c-a d) \left (c+d x^n\right )} \]
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Rubi [A] time = 0.52, antiderivative size = 211, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.097, Rules used = {595, 597, 364} \[ \frac {(e x)^{m+1} \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {d x^n}{c}\right ) (a d (B c (m+1)-A d (m-n+1))+b c (A d (m-2 n+1)-B c (m-n+1)))}{c^2 e (m+1) n (b c-a d)^2}+\frac {b (e x)^{m+1} (A b-a B) \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {b x^n}{a}\right )}{a e (m+1) (b c-a d)^2}+\frac {(e x)^{m+1} (B c-A d)}{c e n (b c-a d) \left (c+d x^n\right )} \]
Antiderivative was successfully verified.
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Rule 364
Rule 595
Rule 597
Rubi steps
\begin {align*} \int \frac {(e x)^m \left (A+B x^n\right )}{\left (a+b x^n\right ) \left (c+d x^n\right )^2} \, dx &=\frac {(B c-A d) (e x)^{1+m}}{c (b c-a d) e n \left (c+d x^n\right )}+\frac {\int \frac {(e x)^m \left (-a (B c-A d) (1+m)+A (b c-a d) n-b (B c-A d) (1+m-n) x^n\right )}{\left (a+b x^n\right ) \left (c+d x^n\right )} \, dx}{c (b c-a d) n}\\ &=\frac {(B c-A d) (e x)^{1+m}}{c (b c-a d) e n \left (c+d x^n\right )}+\frac {\int \left (\frac {b (A b-a B) c n (e x)^m}{(b c-a d) \left (a+b x^n\right )}+\frac {(b c (A d (1+m-2 n)-B c (1+m-n))+a d (B c (1+m)-A d (1+m-n))) (e x)^m}{(b c-a d) \left (c+d x^n\right )}\right ) \, dx}{c (b c-a d) n}\\ &=\frac {(B c-A d) (e x)^{1+m}}{c (b c-a d) e n \left (c+d x^n\right )}+\frac {(b (A b-a B)) \int \frac {(e x)^m}{a+b x^n} \, dx}{(b c-a d)^2}+\frac {(b c (A d (1+m-2 n)-B c (1+m-n))+a d (B c (1+m)-A d (1+m-n))) \int \frac {(e x)^m}{c+d x^n} \, dx}{c (b c-a d)^2 n}\\ &=\frac {(B c-A d) (e x)^{1+m}}{c (b c-a d) e n \left (c+d x^n\right )}+\frac {b (A b-a B) (e x)^{1+m} \, _2F_1\left (1,\frac {1+m}{n};\frac {1+m+n}{n};-\frac {b x^n}{a}\right )}{a (b c-a d)^2 e (1+m)}+\frac {(b c (A d (1+m-2 n)-B c (1+m-n))+a d (B c (1+m)-A d (1+m-n))) (e x)^{1+m} \, _2F_1\left (1,\frac {1+m}{n};\frac {1+m+n}{n};-\frac {d x^n}{c}\right )}{c^2 (b c-a d)^2 e (1+m) n}\\ \end {align*}
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Mathematica [A] time = 0.25, size = 150, normalized size = 0.71 \[ \frac {x (e x)^m \left (b c^2 (A b-a B) \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {b x^n}{a}\right )+a c d (a B-A b) \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {d x^n}{c}\right )+a (b c-a d) (B c-A d) \, _2F_1\left (2,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {d x^n}{c}\right )\right )}{a c^2 (m+1) (b c-a d)^2} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.65, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (B x^{n} + A\right )} \left (e x\right )^{m}}{b d^{2} x^{3 \, n} + a c^{2} + {\left (2 \, b c d + a d^{2}\right )} x^{2 \, n} + {\left (b c^{2} + 2 \, a c d\right )} x^{n}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (B x^{n} + A\right )} \left (e x\right )^{m}}{{\left (b x^{n} + a\right )} {\left (d x^{n} + c\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 1.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (B \,x^{n}+A \right ) \left (e x \right )^{m}}{\left (b \,x^{n}+a \right ) \left (d \,x^{n}+c \right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {{\left (B c e^{m} - A d e^{m}\right )} x x^{m}}{b c^{3} n - a c^{2} d n + {\left (b c^{2} d n - a c d^{2} n\right )} x^{n}} - {\left ({\left (a d^{2} e^{m} {\left (m - n + 1\right )} - b c d e^{m} {\left (m - 2 \, n + 1\right )}\right )} A + {\left (b c^{2} e^{m} {\left (m - n + 1\right )} - a c d e^{m} {\left (m + 1\right )}\right )} B\right )} \int \frac {x^{m}}{b^{2} c^{4} n - 2 \, a b c^{3} d n + a^{2} c^{2} d^{2} n + {\left (b^{2} c^{3} d n - 2 \, a b c^{2} d^{2} n + a^{2} c d^{3} n\right )} x^{n}}\,{d x} - {\left (B a b e^{m} - A b^{2} e^{m}\right )} \int \frac {x^{m}}{a b^{2} c^{2} - 2 \, a^{2} b c d + a^{3} d^{2} + {\left (b^{3} c^{2} - 2 \, a b^{2} c d + a^{2} b d^{2}\right )} x^{n}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (e\,x\right )}^m\,\left (A+B\,x^n\right )}{\left (a+b\,x^n\right )\,{\left (c+d\,x^n\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: HeuristicGCDFailed} \]
Verification of antiderivative is not currently implemented for this CAS.
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